document.write( "Question 24439: Mike's age is three-fourths of Mary's age. In 5 years Mike's age will be 7/9 Mary's age. How old is Mike now? \n" ); document.write( "
Algebra.Com's Answer #13015 by Paul(988)\"\" \"About 
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mike's age = 3x/4
\n" ); document.write( "Mary's age = x\r
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\n" ); document.write( "\n" ); document.write( "In five years mike's age = 3x/4+5
\n" ); document.write( "Mary's age in five years = 7/9(x+5)\r
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\n" ); document.write( "\n" ); document.write( "7/9(x+5) = 3x/4+5
\n" ); document.write( "7x+35/9=3x/4+5 -> commom denomenator = 36
\n" ); document.write( "36(7x+35/9=3x/4+5)--> simplify
\n" ); document.write( "28x+140=27x+180 --> simplify
\n" ); document.write( "x = 40\r
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\n" ); document.write( "\n" ); document.write( "\"%283+x+40%29%2F4\" = 30\r
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\n" ); document.write( "\n" ); document.write( "Hence Mary's age is 40, and Mike's age is 30.
\n" ); document.write( "Paul.
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