document.write( "Question 24439: Mike's age is three-fourths of Mary's age. In 5 years Mike's age will be 7/9 Mary's age. How old is Mike now? \n" ); document.write( "
Algebra.Com's Answer #13015 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! mike's age = 3x/4 \n" ); document.write( "Mary's age = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In five years mike's age = 3x/4+5 \n" ); document.write( "Mary's age in five years = 7/9(x+5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7/9(x+5) = 3x/4+5 \n" ); document.write( "7x+35/9=3x/4+5 -> commom denomenator = 36 \n" ); document.write( "36(7x+35/9=3x/4+5)--> simplify \n" ); document.write( "28x+140=27x+180 --> simplify \n" ); document.write( "x = 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence Mary's age is 40, and Mike's age is 30. \n" ); document.write( "Paul. \n" ); document.write( " |