document.write( "Question 174766This question is from textbook Saxon Algebra 2
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document.write( ": Find the inverse of \r
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document.write( "A= (matrix) -3....1
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document.write( " -5....5\r
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document.write( "if it exists. \n" );
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Algebra.Com's Answer #130140 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! We know that the matrix has an inverse because the determinant is not equal to zero\r \n" ); document.write( "\n" ); document.write( "[-3 1] \n" ); document.write( "[-5 5]\r \n" ); document.write( "\n" ); document.write( "[a b] \n" ); document.write( "[c d]\r \n" ); document.write( "\n" ); document.write( "To calculate the determinant ad-bc in this case -15+5=-10\r \n" ); document.write( "\n" ); document.write( "Any Matrix inverse =1/ad-bc[d -b] \n" ); document.write( " [-c a]\r \n" ); document.write( "\n" ); document.write( "-1/10[5 -1] \n" ); document.write( " [5 -3]\r \n" ); document.write( "\n" ); document.write( "To double check multiply the matrices together and see if you come up with the identity matrix.\r \n" ); document.write( "\n" ); document.write( "[-3 1]-1/10[5 -1] \n" ); document.write( "[-5 5] [5 -3]\r \n" ); document.write( "\n" ); document.write( "-15+5 3+3 -1/10[-10 0]\r \n" ); document.write( "\n" ); document.write( "-25+25 5-15 -1/10[0 -10]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "[1 0] \n" ); document.write( "[0 1] is the identity matrix\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |