document.write( "Question 175025:
\n" ); document.write( "Find the missing root and solve for k: 2x^2 - 12x + k = 0; r1 = 3 + square root of 2 \n" ); document.write( "

Algebra.Com's Answer #130138 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Find the missing root and solve for k:
\n" ); document.write( " 2x^2 - 12x + k = 0;
\n" ); document.write( "r1 = 3 + $\"sqrt%282%29\"$
\n" ); document.write( "r2 = 3 - $\"sqrt%282%29\"$
\n" ); document.write( ":
\n" ); document.write( "Find k:
\n" ); document.write( "x = 3 + $\"sqrt%282%29\"$
\n" ); document.write( "x - 3 = $\"sqrt%282%29\"$
\n" ); document.write( "square both sides
\n" ); document.write( "(x-3)^2 = ( $\"sqrt%282%29\"$ )^2
\n" ); document.write( ":
\n" ); document.write( "x^2 - 6x + 9 = 2
\n" ); document.write( ":
\n" ); document.write( "x^2 - 6x + 9 - 2 = 0
\n" ); document.write( ":
\n" ); document.write( "x^2 - 6x + 7 = 0
\n" ); document.write( ":
\n" ); document.write( "I left a step out here
\n" ); document.write( "2(x^2 - 6x + 7) = 2x - 12x + 14; the original equation
\n" ); document.write( "therefore
\n" ); document.write( "k = 14
\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "

\n" );