document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175034>Question 175034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is three time as old as his son in 13 years time. the father will only be twice as old as his son. find their present ages ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130136 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=son's present age; x+13=son's age in 13 years<BR>\n" );
document.write( "Then 3x=father's present age; 3x+13=father's age in 13 years\r<BR>\n" );
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document.write( "Now we are told the following:<BR>\n" );
document.write( "3x+13=2(x+13)  get rid of parens<BR>\n" );
document.write( "3x+13=2x+26 subtract 13 and also 2x from each side<BR>\n" );
document.write( "3x-2x+13-13=2x-2x+26-13  collect like terms<BR>\n" );
document.write( "x=13----------------------------son's present age<BR>\n" );
document.write( "3x=3*13=39-------------------------father's present age\r<BR>\n" );
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document.write( "39+13=2*(13+13)<BR>\n" );
document.write( "52=2*26<BR>\n" );
document.write( "52=52\r<BR>\n" );
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document.write( "Doess this help?----ptaylor<BR>\n" );
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