document.write( "Question 175036: find two consecutive odd number such that when smaller number is subtracted from 3 time bigger number, the result is 56. \n" ); document.write( "
Algebra.Com's Answer #130134 by ptaylor(2198)\"\" \"About 
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Let x=the first odd number
\n" ); document.write( "Then x+2=the second or bigger odd number\r
\n" ); document.write( "\n" ); document.write( "3(x+2)=three times the bigger odd number
\n" ); document.write( "Now we are told the following:
\n" ); document.write( "3(x+2)-x=56 get rid of parens (distributive)
\n" ); document.write( "3x+6-x=56 subtract 6 from each side
\n" ); document.write( "3x+6-6-x=56-6 collect like terms
\n" ); document.write( "2x=50 divide each side by 2
\n" ); document.write( "x=25--------------------------first odd number
\n" ); document.write( "x+2=25+2=27-----------------------second odd number\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "3*27-25=56
\n" ); document.write( "81-25=56
\n" ); document.write( "56=56\r
\n" ); document.write( "\n" ); document.write( "Does this help?---ptaylor
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