document.write( "Question 175031: what is equal to x^2-5x+6?\r
\n" ); document.write( "\n" ); document.write( "a. (x-2) (x-3)
\n" ); document.write( "b. (x-2) (x+3)
\n" ); document.write( "c. (x+6) (x-1)
\n" ); document.write( "d. (x-6) (x+1)\r
\n" ); document.write( "\n" ); document.write( "i think the answer is A but I wanted make sure.. thanks :o)
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Algebra.Com's Answer #130128 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2-5x%2B6\", we can see that the first coefficient is \"1\", the second coefficient is \"-5\", and the last term is \"6\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"6\" to get \"%281%29%286%29=6\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"6\" (the previous product) and add to the second coefficient \"-5\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"6\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"6\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"6\".\r
\n" ); document.write( "\n" ); document.write( "1*6
\n" ); document.write( "2*3
\n" ); document.write( "(-1)*(-6)
\n" ); document.write( "(-2)*(-3)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-5\":\r
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First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-2\" and \"-3\" add to \"-5\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-2\" and \"-3\" both multiply to \"6\" and add to \"-5\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-5x\" with \"-2x-3x\". Remember, \"-2\" and \"-3\" add to \"-5\". So this shows us that \"-2x-3x=-5x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%28-2x-3x%29%2B6\" Replace the second term \"-5x\" with \"-2x-3x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-2x%29%2B%28-3x%2B6%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-2%29%2B%28-3x%2B6%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-2%29-3%28x-2%29\" Factor out \"3\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%28x-2%29\" Combine like terms. Or factor out the common term \"x-2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-5x%2B6\" factors to \"%28x-3%29%28x-2%29\".\r
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\n" ); document.write( "\n" ); document.write( "This means that \"x%5E2-5x%2B6=%28x-3%29%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing \"%28x-3%29%28x-2%29\" to get \"x%5E2-5x%2B6\" or by graphing the original expression and the answer (the two graphs should be identical).
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