document.write( "Question 24435: I understand how to do these but for sme reason this one is giving me a problem could you please help?\r
\n" ); document.write( "\n" ); document.write( "Use sustitution to solve: 2x+y=7
\n" ); document.write( " 5x-2y=4\r
\n" ); document.write( "\n" ); document.write( "thank you
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Algebra.Com's Answer #13012 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve by substitution:
\n" ); document.write( "1) \"2x%2By+=+7\" Write this in terms of y:
\n" ); document.write( "1a)\"y+=+-2x%2B7\" and substitute into equation 2) then solve for x.
\n" ); document.write( "2) \"5x-2y+=+4\"\r
\n" ); document.write( "\n" ); document.write( "\"5x-2%28-2x%2B7%29+=+4\" Simplify and solve for x.
\n" ); document.write( "\"5x%2B4x-14+=+4\"
\n" ); document.write( "\"9x-14+=+4\" Add 14 to both sides of the equation.
\n" ); document.write( "\"9x+=+18\" Divide both sides by 9.
\n" ); document.write( "\"x+=+2\" Now substitute this value of x into equation 1a) and solve for y.\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-2x%2B7\"
\n" ); document.write( "\"y+=+-2%282%29%2B7\"
\n" ); document.write( "\"y+=+-4%2B7\"
\n" ); document.write( "\"y+=+3\"\r
\n" ); document.write( "\n" ); document.write( "The solution is: (2, 3)
\n" ); document.write( "Here's the graphical solution: Red line is:\"y+=+-2x%2B7\" Green line is:\"y+=+%285%2F2%29x-2\"
\n" ); document.write( "\"graph%28300%2C200%2C-5%2C5%2C-5%2C8%2C-2x%2B7%2C%285%2F2%29x-2%29\"
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