document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175001>Question 175001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i find the equation of the line that passes through the points (-2,2) and (0,5)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130095 by </B><A HREF=/tutors/aboutme.mpl?userid=actuary><B>actuary(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=actuary><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since two points are given, you first need to find the slope (m) of the line.\r<BR>\n" );
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document.write( "This is the general formula for the slope.\r<BR>\n" );
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document.write( "m=(y2-y1)/(x2-x1)  Substituting the actual values into the formula we have\r<BR>\n" );
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document.write( "m = (5-2)/(0-(-2))= 3/2\r<BR>\n" );
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document.write( "Now you can use the point-slope formula\r<BR>\n" );
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document.write( "(y-2)=3/2*(x-(-2))\r<BR>\n" );
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document.write( "So y = 3/2x+3+2= (3/2)x+5\r<BR>\n" );
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document.write( "As a check, substitute the value for x=0 for the other given point.\r<BR>\n" );
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document.write( "y=(3/2)*0+5=5 (Checks out OK)\r<BR>\n" );
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document.write( "I hope that this helps\r<BR>\n" );
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