document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174972>Question 174972</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two 12 mm sides of a rhombus form a 60 degree angle. Fine the area of the rhombus. Round your answer to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130089 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two 12 mm sides of a rhombus form a 60 degree angle. Fine the area of the rhombus. Round your answer to the nearest tenth.<BR>\n" );
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document.write( "You can use trig to find the area here: A = side^2 * sine of an interior angle<BR>\n" );
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document.write( "A = 12^2 * sin(60)<BR>\n" );
document.write( "A = 144 * .866<BR>\n" );
document.write( "A = 124.7 sq/mm </SPAN>\n" );
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