document.write( "Question 174996: If a line passes through the point (-1,3) and has a slop of 2. How do I find another point? \n" ); document.write( "
Algebra.Com's Answer #130081 by actuary(112)![]() ![]() ![]() You can put this solution on YOUR website! First write the equation of the line\r \n" ); document.write( "\n" ); document.write( "In point slope form, the equation is\r \n" ); document.write( "\n" ); document.write( "y-3=2*(x-(-1))\r \n" ); document.write( "\n" ); document.write( "This can be written in slope y-intercept form\r \n" ); document.write( "\n" ); document.write( "y=2*x+2+3 = 2*x+5\r \n" ); document.write( "\n" ); document.write( "This line goes through the point(-1,3)\r \n" ); document.write( "\n" ); document.write( "Select the \"x\" value for another point, say x=2.\r \n" ); document.write( "\n" ); document.write( "Replace the variable \"x\" in the equation with the value of x which is 2.\r \n" ); document.write( "\n" ); document.write( "Y= 2*2+5=9\r \n" ); document.write( "\n" ); document.write( "So another point on the line is (2,9) \n" ); document.write( " |