document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174996>Question 174996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a line passes through the point (-1,3) and has a slop of 2. How do I find another point? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130077 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a line passes through the point (-1,3) and has a slop of 2. How do I find another point?<BR>\n" );
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document.write( "One way is to find the equation, then find any number of points.<BR>\n" );
document.write( "Use y-y1 = m*(x-x1) where m is the slope and (x1,y1) is the point (-1,3)<BR>\n" );
document.write( "y-3 = 2*(x+1) = 2x+2<BR>\n" );
document.write( "y = 2x + 5<BR>\n" );
document.write( "Then insert a value for x and find y<BR>\n" );
document.write( "eg, x=0, y=5 --> (0,5)<BR>\n" );
document.write( "x= 1/3, y = 17/3 --> (1/3,17/3)<BR>\n" );
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document.write( "Another way is to add/subtract 2 to y for each 1 to x.<BR>\n" );
document.write( "Points = (-1+2q,3+q) for any value of q\r<BR>\n" );
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