document.write( "Question 174982: the park's width is 70m more than half the length with the total perimeter of 1280m what is the width and length of the park's perimeter \n" ); document.write( "
Algebra.Com's Answer #130071 by actuary(112)![]() ![]() ![]() You can put this solution on YOUR website! The width of the park is w and thelength is l.\r \n" ); document.write( "\n" ); document.write( "The equations that describe the situation are:\r \n" ); document.write( "\n" ); document.write( "2l+2w=1280m (Equation #1)\r \n" ); document.write( "\n" ); document.write( "w = (1/2)*l+70 (Equation #2)\r \n" ); document.write( "\n" ); document.write( "Equation #1 can be rewritten as l = 640 - w\r \n" ); document.write( "\n" ); document.write( "Substitute the value for l into equation #2\r \n" ); document.write( "\n" ); document.write( "w = 1/2(640-w)+70 = 320 -(1/2)*w + 70\r \n" ); document.write( "\n" ); document.write( "Putting the unknowns on one side of the quation.\r \n" ); document.write( "\n" ); document.write( "w+(1/2)w=390\r \n" ); document.write( "\n" ); document.write( "3/2w = 390\r \n" ); document.write( "\n" ); document.write( "Solve for w \r \n" ); document.write( "\n" ); document.write( "w = 390*(2/3) = 260 m\r \n" ); document.write( "\n" ); document.write( "Substituting the value for w into equation #1, we have\r \n" ); document.write( "\n" ); document.write( "2*l+2*(260m)=1280m\r \n" ); document.write( "\n" ); document.write( "2*l = 1280m-520m = 760m\r \n" ); document.write( "\n" ); document.write( "Solve for l\r \n" ); document.write( "\n" ); document.write( "l = 380m\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |