document.write( "Question 174982: the park's width is 70m more than half the length with the total perimeter of 1280m what is the width and length of the park's perimeter \n" ); document.write( "
Algebra.Com's Answer #130068 by ankor@dixie-net.com(22740)\"\" \"About 
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the park's width is 70m more than half the length
\n" ); document.write( "W = .5L + 70
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\n" ); document.write( "the total perimeter of 1280m
\n" ); document.write( "2L + 2W = 1280
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\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "L + W = 640
\n" ); document.write( "Substitute (.5L+70) for W in the above equation
\n" ); document.write( "L + (.5L + 70) = 640
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\n" ); document.write( "1.5L = 640 - 70
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\n" ); document.write( "1.5L = 570
\n" ); document.write( "L = \"570%2F1.5\"
\n" ); document.write( "L = 380 meters is the length
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\n" ); document.write( "Find the width
\n" ); document.write( "W = .5(380 + 70)
\n" ); document.write( "W = 190 + 70
\n" ); document.write( "W = 260 m is the width
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\n" ); document.write( "Check solution in the perimeter equation
\n" ); document.write( "2(380) + 2(260) =
\n" ); document.write( "760 + 520 = 1280m confirms our solution\r
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