document.write( "Question 174987: if 5(p-4) + 3 = 2p then p =\r
\n" ); document.write( "\n" ); document.write( "a. 1/3
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\n" ); document.write( "c. 17/3
\n" ); document.write( "d. 6\r
\n" ); document.write( "\n" ); document.write( "I am very confused by this question and cannot find help in my textbook.. please help!
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Algebra.Com's Answer #130052 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"5%28p-4%29%2B3=2p\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"5p-20%2B3=2p\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"5p-17=2p\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"5p=2p%2B17\" Add \"17\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"5p-2p=17\" Subtract \"2p\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3p=17\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"p=%2817%29%2F%283%29\" Divide both sides by \"3\" to isolate \"p\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"p=17%2F3\" which approximates to \"p=5.667\". \r
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