document.write( "Question 174952: The differece between two positive numbers is 4. If twice the square of the larger number is added to three times the smaller number ,the sum is 53.What is the steps to the solution? \n" ); document.write( "

Algebra.Com's Answer #130048 by Alan3354(69443) $\"\"$ $\"About$

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The difference between two positive numbers is 4. If twice the square of the larger number is added to three times the smaller number ,the sum is 53.What is the steps to the solution?
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\n" ); document.write( "EQUATIONS:
\n" ); document.write( "x - y = 4
\n" ); document.write( "2x^2 + 3y = 53
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\n" ); document.write( "Sub y = x-4 into the 2nd eqn
\n" ); document.write( "2x^2 + 3(x-4) = 53
\n" ); document.write( "2x^2 + 3x - 65 = 0
\n" ); document.write( "---
\n" ); document.write( " $\"x+=+%28-3+%2B-+sqrt%289+-+4%2A2%2A-65%29%29%2F4+\"$
\n" ); document.write( "x = 5, x = -6.5
\n" ); document.write( "Only the positive is asked for, so ignore the -6.5
\n" ); document.write( "x = 5
\n" ); document.write( "y = 9
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