document.write( "Question 174953: The area of a rectangle is the product of its length and width , and equals 1062.If the length is 5 more than three times the width ,find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #130044 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "The area of a rectangle is the product of its length and width, and equals 1062. \n" ); document.write( "L * W = 1062 \n" ); document.write( ": \n" ); document.write( "the length is 5 more than three times the width, \n" ); document.write( "L = 3W + 5 \n" ); document.write( ": \n" ); document.write( "find the width of the rectangle. \n" ); document.write( ": \n" ); document.write( "Replace L with (3W+5) in the 1st equation: \n" ); document.write( "(3W+5) * W = 1062 \n" ); document.write( ": \n" ); document.write( "3W^2 + 5W = 1062 \n" ); document.write( ": \n" ); document.write( "3W^2 + 5W - 1062 = 0; our old friend the quadratic equation! \n" ); document.write( ": \n" ); document.write( "You can use the quadratic formula, however, this will factors to: \n" ); document.write( "(3W-54)(W+59) = 0 \n" ); document.write( ": \n" ); document.write( "The positive solution: \n" ); document.write( "3W = +54 \n" ); document.write( "W = 54/3 \n" ); document.write( "W = 18 is the width \n" ); document.write( "Find the length \n" ); document.write( "3(18) + 5 = 59 is the length \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions: \n" ); document.write( "59 * 18 = 1062 \n" ); document.write( " \n" ); document.write( " |