document.write( "Question 174973: I need help!!
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document.write( "- A car travelled 470 km from Sudbury to Brandford in 5 hours. For part of the trip, the car travelled at 100 km/h. For the rest of the trip, it travelled at 90 km/h. How far did the car travel at each speed?\r
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document.write( "I tried
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document.write( "x+y=5
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document.write( "100x+90=470\r
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document.write( "100x+100y=500
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document.write( "100x+90y=470\r
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document.write( "= 10y = 30
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document.write( "x=2 y=3
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document.write( "but I only got half marks. Where did I go wrong and what was the answer? \n" );
document.write( "
Algebra.Com's Answer #130043 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A car travelled 470 km from Sudbury to Brandford in 5 hours. For part of the trip, the car traveled at 100 km/h. For the rest of the trip it traveled at 90 km/h. How far did the car travel at each speed? \n" ); document.write( "-------------------------- \n" ); document.write( "100 kph section DATA: \n" ); document.write( "Distance = x km ; rate = 100 kph ; time = d/r = x/100 hrs. \n" ); document.write( "-------------------- \n" ); document.write( "90 kph section DATA: \n" ); document.write( "Distance = 470 - x km ; rate = 90 kph ; time = d/r = (470-x)/90 hrs \n" ); document.write( "========================== \n" ); document.write( "EQUATION: \n" ); document.write( "time + time = 5 hrs \n" ); document.write( "x/100 + (470-x)/90 = 5 \n" ); document.write( "90x + 100(470-x) = 450*100 \n" ); document.write( "90x + 100*470 - 100x = 450*100 \n" ); document.write( "-10x = -20*100 \n" ); document.write( "x = 200 km (distance traveled at 100 kph) \n" ); document.write( "470-x = 270 km (distance traveled at 90 kph) \n" ); document.write( "================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |