document.write( "Question 174976: Could someone help me out?
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document.write( "How much of a 40% antifreeze solution must a mechanical mix with an 80% antifreeze solution if 20 L of a 50% antifreeze solution are need?\r
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document.write( "I tried the following and was marked wrong.
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document.write( "Let c represent the 40% solution
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document.write( "___ y _____________ 80% ________\r
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document.write( "x + y= 20
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document.write( "40x+80y= 50
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document.write( "40x+40y=8
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document.write( "40x+40y=.5
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document.write( "-4y=7.5
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document.write( "y=18.75
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document.write( "x+18.75=20
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document.write( "x=1.25 y= 18.75 \n" );
document.write( "
Algebra.Com's Answer #130039 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much of a 40% antifreeze solution must a mechanic mix with an 80% antifreeze solution if 20 L of a 50% antifreeze solution are needed? \n" ); document.write( "------------------------ \n" ); document.write( "active + active = active \n" ); document.write( "0.40x + 0.80(20-x) = 0.50*20 \n" ); document.write( "40x + 1600 - 80x = 1000 \n" ); document.write( "-40x = -600 \n" ); document.write( "x = 15 liters (amount of 40% antifreeze needed in the mixture) \n" ); document.write( "------------- \n" ); document.write( "20-x = 5 liters (amount of 80% antifreeze needed in the mixture) \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |