document.write( "Question 174952: The differece between two positive numbers is 4. If twice the square of the larger number is added to three times the smaller number ,the sum is 53.What is the steps to the solution? \n" ); document.write( "
Algebra.Com's Answer #130012 by stanbon(75887)\"\" \"About 
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The difference between two positive numbers is 4. If twice the square of the larger number is added to three times the smaller number ,the sum is 53.What is the steps to the solution?
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\n" ); document.write( "EQUATIONS:
\n" ); document.write( "x - y = 4
\n" ); document.write( "2x^2 + 3y = 53
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\n" ); document.write( "Substitute y = x-4 into the 2nd equation to solve for \"x\":
\n" ); document.write( "2x^2 + 3(x-4) = 53
\n" ); document.write( "2x^2 + 3x - 65 = 0
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\n" ); document.write( "\n" ); document.write( "x = [-3 +- sqrt(9 - 4*2*-65)]/4\r
\n" ); document.write( "\n" ); document.write( "x = [-3 +- 23]/4\r
\n" ); document.write( "\n" ); document.write( "x = [-3 +23]/4 = 5
\n" ); document.write( "Then y = x+4 = 9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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