document.write( "Question 174936: Please help me solve this equations: \"a%2B2c%2B3e%2B2f=270\" \n" ); document.write( "
Algebra.Com's Answer #130003 by checkley75(3666)\"\" \"About 
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\"a%2B2c%2B3e%2B2f=270\"
\n" ); document.write( "There is no UNIQUE solution to this equation because you have 4 unknowns & only one equation.
\n" ); document.write( "However you can make up a table & find many combinations od a, c, e & f that satisfus this equation thus:
\n" ); document.write( "a---2c---3e---2f=270
\n" ); document.write( "50+2*25+3*10+2*70=270
\n" ); document.write( "50+50+30+140=270
\n" ); document.write( "OR
\n" ); document.write( "100+2*10+3*20+2*45=270
\n" ); document.write( "100+20+60+90=270
\n" ); document.write( "270=270
\n" ); document.write( "And there are many additional combinations of a,c,e & f that are solutions.\r
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