document.write( "Question 24417: Please show me step by step how to divide:\r
\n" ); document.write( "\n" ); document.write( "(x^3 + 5x^2 - 10) by (x + 3)\r
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Algebra.Com's Answer #12999 by kev82(151)\"\" \"About 
You can put this solution on YOUR website!
Hi,\r
\n" ); document.write( "\n" ); document.write( "When I first learnt to do this, I found it really hard. But if you keep practicing it will become second nature, trust me.\r
\n" ); document.write( "\n" ); document.write( "Before I go through your problem let me point you to this really good explanation. If you can follow that and do the practice ones on there, then you should find this easy.\r
\n" ); document.write( "\n" ); document.write( "I would like to draw the division out as I do it, but it would take me hours to type it in here, so we'll see how you get on. If you still can't do it email me and I'll write it down on paper and scan it in for you.\r
\n" ); document.write( "\n" ); document.write( "How many times does \"x%2B3\" go into \"x%5E3\"? The answer is \"x%5E2\" because \"%28x%2B3%29x%5E2=x%5E3%2B3x%5E2\". So we know the answer has \"x%5E2\" in it, and we have \"x%5E3+%2B+5x%5E2+-+10+-+%28x%5E3%2B3x%5E2%29+=+2x%5E2+-10\" left.\r
\n" ); document.write( "\n" ); document.write( "So we now need to work out \"2x%5E2-10\" divided by \"x%2B3\". Asking the same question as before we can see that \"x%2B3\" goes into \"2x%5E2\" \"2x\" times. The remainder is \"2x%5E2-10+-+2x%28x%2B3%29=-6x-10\".\r
\n" ); document.write( "\n" ); document.write( "So we know that the final answer is \"x%5E2\" plus \"2x\" plus \"-6x-10\" divided by \"x%2B3\"\r
\n" ); document.write( "\n" ); document.write( "Repeating the same process \"x%2B3\" goes into \"-6x-10\" \"-6\" times, with remainder \"-6x-10+-+-6%28x%2B3%29=8\". At this point we stop because \"x%2B3\" doesn't go into 8. So the final answer is:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B2x-6%2B8%2F%28x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "The last term is the remainder, because there isn't anything else we can do with it. Don't forget to check your answer is right by multiplying that by \"x%2B3\" and checking you get the original expression.\r
\n" ); document.write( "\n" ); document.write( "Hope that helps, and if you need me to send you the working written down, then please email back.\r
\n" ); document.write( "\n" ); document.write( "Kev
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