document.write( "Question 174924: The product of two consecutive even integers decreased by seven times the greater integer is 70. Find the two integers.\r
\n" ); document.write( "\n" ); document.write( "I started the problem off this way:
\n" ); document.write( "http://img229.imageshack.us/img229/8166/dtuyhsrxujt0.png
\n" ); document.write( "but now I'm lost, clearly. It looks like I'll be going into a degree of three, which doesn't make sense.\r
\n" ); document.write( "\n" ); document.write( "If you could perhaps show me where I went wrong, I'd really appreciate it. Thanks. \n" ); document.write( "
Algebra.Com's Answer #129981 by nerdybill(7384)\"\" \"About 
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The product of two consecutive even integers decreased by seven times the greater integer is 70. Find the two integers.
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\n" ); document.write( "Let x = 1st consecutive event integer
\n" ); document.write( "then
\n" ); document.write( "x+2 = 2nd consecutive even integer
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\n" ); document.write( "x(x+2) - 7(x+2) = 70
\n" ); document.write( "x^2+2x - 7x-14 = 70
\n" ); document.write( "x^2- 5x-14 = 70
\n" ); document.write( "x^2- 5x-84 = 0
\n" ); document.write( "(x-12)(x+7) = 0
\n" ); document.write( "x = {12,-7}
\n" ); document.write( "Tossing out the odd solution, we're left with:
\n" ); document.write( "x = 12 (1st even integer)
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\n" ); document.write( "x+2 = 12+2 = 14 (2nd even integer) \n" ); document.write( "
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