document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=167853>Question 167853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE PERIMETER OF A TRIANGLE IS 378 YARDS. THE SHORTEST SIDE IS 30 YARDS LONGER THAN ONE-HALF OF THE LONGEST SIDE. THE SECOND LONGEST SIDE IS 2 YARDS SHORTER THAN THE LONGEST SIDE. WHAT IS THE LENGTH OF EACH SIDE? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129978 by </B><A HREF=/tutors/aboutme.mpl?userid=piyushkumar47><B>piyushkumar47(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=piyushkumar47><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the sides of triangle be ABC.<BR>\n" );
document.write( "Let the longest side ie hypotenuse(AB) be x , then <BR>\n" );
document.write( "base(CB) will be 30+1x/2 and perpendicular will be x-2.<BR>\n" );
document.write( "perimeter of triangle = 378 yards \r<BR>\n" );
document.write( "\n" );
document.write( "according to the question <BR>\n" );
document.write( "x+ 30+1x/2+x-2= 378<BR>\n" );
document.write( "2x+60+x+2x-4/2                                 {on taking L.C.M.}<BR>\n" );
document.write( "5x+56/2 = 378<BR>\n" );
document.write( "5x+56 = 378*2<BR>\n" );
document.write( "5x    = 756-56<BR>\n" );
document.write( "x     = 700/5<BR>\n" );
document.write( "x     = 140<BR>\n" );
document.write( "Ans. AB = 140 <BR>\n" );
document.write( "     BC = 100<BR>\n" );
document.write( "     Cd = 138   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );