document.write( "Question 174880: solve the logarithm\r
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\n" ); document.write( "\n" ); document.write( "2log3z-log3(z-2)=2
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Algebra.Com's Answer #129950 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%2Alog%283%2C%28z%29%29-log%283%2C%28z-2%29%29=2\" Start with the given equation. \r
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\n" ); document.write( "\n" ); document.write( "Take note that \"z%3E0\" (for the first log) and \"z-2%3E0\"---> \"z%3E2\" (for the second log). \r
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\n" ); document.write( "\n" ); document.write( "So the domain is \"z%3E2\" (this interval works for BOTH logs)\r
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\n" ); document.write( "\n" ); document.write( "\"log%283%2C%28z%5E2%29%29-log%283%2C%28z-2%29%29=2\" Rewrite the first log using the identity \"y%2Alog%28b%2C%28x%29%29=log%28b%2C%28x%5Ey%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%283%2C%28%28z%5E2%29%2F%28z-2%29%29%29=2\" Combine the logs using the identity \"log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%5E2=%28z%5E2%29%2F%28z-2%29\" Rewrite the equation using the property: \"log%28b%2C%28x%29%29=y\" ====> \"b%5Ey=x\"\r
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\n" ); document.write( "\n" ); document.write( "\"9=%28z%5E2%29%2F%28z-2%29\" Square 3 to get 9\r
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\n" ); document.write( "\n" ); document.write( "\"9%28z-2%29=z%5E2\" Multiply both sides by \"z-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"9z-18=z%5E2\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"-z%5E2%2B9z-18=0\" Subtract \"z%5E2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"az%5E2%2Bbz%2Bc\" where \"a=-1\", \"b=9\", and \"c=-18\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for z\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-%289%29+%2B-+sqrt%28+%289%29%5E2-4%28-1%29%28-18%29+%29%29%2F%282%28-1%29%29\" Plug in \"a=-1\", \"b=9\", and \"c=-18\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-9+%2B-+sqrt%28+81-4%28-1%29%28-18%29+%29%29%2F%282%28-1%29%29\" Square \"9\" to get \"81\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-9+%2B-+sqrt%28+81-72+%29%29%2F%282%28-1%29%29\" Multiply \"4%28-1%29%28-18%29\" to get \"72\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-9+%2B-+sqrt%28+9+%29%29%2F%282%28-1%29%29\" Subtract \"72\" from \"81\" to get \"9\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-9+%2B-+sqrt%28+9+%29%29%2F%28-2%29\" Multiply \"2\" and \"-1\" to get \"-2\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-9+%2B-+3%29%2F%28-2%29\" Take the square root of \"9\" to get \"3\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-9+%2B+3%29%2F%28-2%29\" or \"z+=+%28-9+-+3%29%2F%28-2%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-6%29%2F%28-2%29\" or \"z+=++%28-12%29%2F%28-2%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+3\" or \"z+=+6\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"z+=+3\" or \"z+=+6\" \r
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\n" ); document.write( "Take note that both of these solutions are within the domain \"z%3E2\". So they are valid solutions.
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