document.write( "Question 174882: I have a block with one edge at a known temp. of 200 degrees C. The temp varies through the block according to the equation:\r
\n" ); document.write( "\n" ); document.write( "t = 200 - 5x - x^2\r
\n" ); document.write( "\n" ); document.write( "What is x when t = 50?\r
\n" ); document.write( "\n" ); document.write( "t=temp.
\n" ); document.write( "x=position\r
\n" ); document.write( "\n" ); document.write( "I've tried solving for x and substituting into the original equation, but it's been a long time since i had algebra, and i'm doing something wrong. this appears to be a very problem, and i'm feeling might stupid right now. any help is greatly appreciated.
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Algebra.Com's Answer #129946 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"t+=+200+-+5x+-+x%5E2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"t+=++-+x%5E2-+5x%2B200+\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"50+=++-+x%5E2-+5x%2B200+\" Plug in \"t=50\"\r
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\n" ); document.write( "\n" ); document.write( "\"0+=++-+x%5E2-+5x%2B200-50+\" Subtract 50 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0+=++-+x%5E2-+5x%2B150+\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=-1\", \"b=-5\", and \"c=150\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%28-1%29%28150%29+%29%29%2F%282%28-1%29%29\" Plug in \"a=-1\", \"b=-5\", and \"c=150\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%28-1%29%28150%29+%29%29%2F%282%28-1%29%29\" Negate \"-5\" to get \"5\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25-4%28-1%29%28150%29+%29%29%2F%282%28-1%29%29\" Square \"-5\" to get \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25--600+%29%29%2F%282%28-1%29%29\" Multiply \"4%28-1%29%28150%29\" to get \"-600\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+25%2B600+%29%29%2F%282%28-1%29%29\" Rewrite \"sqrt%2825--600%29\" as \"sqrt%2825%2B600%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+625+%29%29%2F%282%28-1%29%29\" Add \"25\" to \"600\" to get \"625\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%28+625+%29%29%2F%28-2%29\" Multiply \"2\" and \"-1\" to get \"-2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+25%29%2F%28-2%29\" Take the square root of \"625\" to get \"25\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B+25%29%2F%28-2%29\" or \"x+=+%285+-+25%29%2F%28-2%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2830%29%2F%28-2%29\" or \"x+=++%28-20%29%2F%28-2%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-15\" or \"x+=+10\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible answers are \"x+=+-15\" or \"x+=+10\" \r
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\n" ); document.write( "\n" ); document.write( "Since \"x\" is the position, this means that a negative position doesn't make sense. So the value \"x+=+-15\" can be ignored.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x+=+10\" which means that at 10 units (or whatever units you're dealing with), the temperature will be 50 degrees.
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