document.write( "Question 174808: A bus and a cyclist leave a school at 8 AM and head for a stadium 90 miles away. The rate of the bus is three times the rate of the cyclist. The cyclist arrives 4 hours after the bus. What is the equation? Find the rate of the bus. \n" ); document.write( "
Algebra.Com's Answer #129880 by stanbon(75887)\"\" \"About 
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A bus and a cyclist leave a school at 8 AM and head for a stadium 90 miles away. The rate of the bus is three times the rate of the cyclist. The cyclist arrives 4 hours after the bus. What is the equation? Find the rate of the bus.
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\n" ); document.write( "Bus DATA:
\n" ); document.write( "distance = 90 miles; rate = 3x mph ; time = d/r = 90/3x = 30/x hours
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\n" ); document.write( "Cyclist DATA:
\n" ); document.write( "distance = 90 miles; rate = x mph ; time = d/r = 90/x hours
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\n" ); document.write( "Equation:
\n" ); document.write( "cyclist time - bus time = 4 hrs.
\n" ); document.write( "90/x - 30/x = 4
\n" ); document.write( "90 - 30 = 4x
\n" ); document.write( "4x = 60
\n" ); document.write( "x = 15 mph (rate of the cyclist)
\n" ); document.write( "3x = 45 mph (rate of the bus)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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