document.write( "Question 174804: what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8? \n" ); document.write( "
Algebra.Com's Answer #129868 by ankor@dixie-net.com(22740)\"\" \"About 
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what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8?
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\n" ); document.write( "The value for b which results in 0 in the denominator, to find that solve for b:
\n" ); document.write( "b^2 - 2b - 8 = 0
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\n" ); document.write( "(b-4)(b+2) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "b = 4
\n" ); document.write( "b = -2
\n" ); document.write( "These are the illegal values for b, substitute these values for b in the denominator to see that we have division by 0 for these values
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