document.write( "Question 174804: what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8? \n" ); document.write( "
Algebra.Com's Answer #129868 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8? \n" ); document.write( ": \n" ); document.write( "The value for b which results in 0 in the denominator, to find that solve for b: \n" ); document.write( "b^2 - 2b - 8 = 0 \n" ); document.write( "Factor \n" ); document.write( "(b-4)(b+2) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "b = 4 \n" ); document.write( "b = -2 \n" ); document.write( "These are the illegal values for b, substitute these values for b in the denominator to see that we have division by 0 for these values \n" ); document.write( " |