document.write( "Question 174804: what is the illegal values of b in the fraction 2b^2+3b-10 over b^2-2b-8? \n" ); document.write( "
Algebra.Com's Answer #129867 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
What are the \"illegal\" values of b in the fraction:
\n" ); document.write( "\"%282b%5E2%2B3b-10%29%2F%28b%5E2-2b-8%29\"
\n" ); document.write( "The \"illegal\" (sometimes called \"excluded\") values of b are those values of b that would make the denominator equal zero. So, we set the denominator equal to zero and solve for b.
\n" ); document.write( "\"b%5E2-2b-8+=+0\" Solve by factoring.
\n" ); document.write( "\"%28b%2B2%29%28b-4%29+=+0\" Apply the zero product rule.
\n" ); document.write( "\"b%2B2+=+0\" or \"b-4+=+0\", so that...
\n" ); document.write( "\"highlight%28b+=+-2%29\" or \"highlight%28b+=+4%29\" These are the \"illegal\" values of b.
\n" ); document.write( "
\n" );