document.write( "Question 174783: 2/3x+8>12
\n" ); document.write( "What i did was:
\n" ); document.write( "2/3x+8-8>12-8 = 2/3x>4
\n" ); document.write( "2/3-2/3x > 4/1*3/2
\n" ); document.write( "= x>6
\n" ); document.write( "this is my answer that i got. x>6
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Algebra.Com's Answer #129856 by actuary(112)\"\" \"About 
You can put this solution on YOUR website!
2/3x+8>12\r
\n" ); document.write( "\n" ); document.write( "2/3x +8-8 > 12-8\r
\n" ); document.write( "\n" ); document.write( "2/3x > 4\r
\n" ); document.write( "\n" ); document.write( "(3/2)*2/3x >(3/2)*4 = 6\r
\n" ); document.write( "\n" ); document.write( "So x > 6\r
\n" ); document.write( "\n" ); document.write( "So, your answer is correct.
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