document.write( "Question 174778: Can you please assist me in the following: A number is ten times the sum of its digits. The tens digit is two greater than the units digit. Find the number.\r
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document.write( "so far I only managed to write:\r
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document.write( "10n=n+m
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document.write( "m=2+10n\r
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document.write( "10n=n+(2+10n)
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document.write( "10n=n+2+10n
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document.write( "10n=11n+2
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document.write( "n=-2\r
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document.write( "10(-2)=(-2)+m
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document.write( "-20=-2+m
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document.write( "m=-18\r
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document.write( "10(-2)=(-2)+(-18)
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document.write( "(-18)=2+10(-2)
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document.write( "-20=-20
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document.write( "-18=-18
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document.write( "would this be the correct answer \n" );
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Algebra.Com's Answer #129853 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The number is \n" ); document.write( "(1) First of all, if a number is \n" ); document.write( "The units digit must be \n" ); document.write( "(2) The problem says the tens digit is two greater \n" ); document.write( "that the units digit, so the tens digit must be \n" ); document.write( "This satisfies the problem \n" ); document.write( "For any number greater than 20, either (1) or (2) is violated, \n" ); document.write( "or ten times the sum of the digits will always be less than \n" ); document.write( "the number itself \n" ); document.write( " |