document.write( "Question 174777: A coin collector had a collection of silver coins worth $205. There were 5 times as many quarters as half-dollars. There were 200 fewer dimes than quarters. How many of each kind of coin did the collector have? \n" ); document.write( "
Algebra.Com's Answer #129852 by checkley75(3666)\"\" \"About 
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Q=5H OR H=Q/5
\n" ); document.write( "D=Q-200 OR Q=D+200
\n" ); document.write( ".50H+.25Q+.10D=205
\n" ); document.write( ".50(Q/5)+.25Q+.10(Q-200)=205
\n" ); document.write( ".10Q+.25Q+.10Q-20=205
\n" ); document.write( ".45Q=205+2-
\n" ); document.write( ".45Q=225
\n" ); document.write( "Q=225/.45
\n" ); document.write( "Q=500 ANS. FOR THE NUMBER OF QUARTERS.
\n" ); document.write( "500=5H
\n" ); document.write( "H=500/5
\n" ); document.write( "H=100 ANS FOR THE NUMBER OF HALVES.
\n" ); document.write( "D=500-200
\n" ); document.write( "D=300 ANS. FOR THE NUMBEROF DIMES.
\n" ); document.write( "PROOF:
\n" ); document.write( ".50*100+.25*500+.10*300=205
\n" ); document.write( "50+125+30=205
\n" ); document.write( "205=205
\n" ); document.write( "
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