document.write( "Question 174777: A coin collector had a collection of silver coins worth $205. There were 5 times as many quarters as half-dollars. There were 200 fewer dimes than quarters. How many of each kind of coin did the collector have? \n" ); document.write( "
Algebra.Com's Answer #129852 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! Q=5H OR H=Q/5 \n" ); document.write( "D=Q-200 OR Q=D+200 \n" ); document.write( ".50H+.25Q+.10D=205 \n" ); document.write( ".50(Q/5)+.25Q+.10(Q-200)=205 \n" ); document.write( ".10Q+.25Q+.10Q-20=205 \n" ); document.write( ".45Q=205+2- \n" ); document.write( ".45Q=225 \n" ); document.write( "Q=225/.45 \n" ); document.write( "Q=500 ANS. FOR THE NUMBER OF QUARTERS. \n" ); document.write( "500=5H \n" ); document.write( "H=500/5 \n" ); document.write( "H=100 ANS FOR THE NUMBER OF HALVES. \n" ); document.write( "D=500-200 \n" ); document.write( "D=300 ANS. FOR THE NUMBEROF DIMES. \n" ); document.write( "PROOF: \n" ); document.write( ".50*100+.25*500+.10*300=205 \n" ); document.write( "50+125+30=205 \n" ); document.write( "205=205 \n" ); document.write( " |