document.write( "Question 174778: Can you please assist me in the following: A number is ten times the sum of its digits. The tens digit is two greater than the units digit. Find the number.\r
\n" ); document.write( "\n" ); document.write( "so far I only managed to write:\r
\n" ); document.write( "\n" ); document.write( "10n=n+m
\n" ); document.write( "m=2+10n\r
\n" ); document.write( "\n" ); document.write( "10n=n+(2+10n)
\n" ); document.write( "10n=n+2+10n
\n" ); document.write( "10n=11n+2
\n" ); document.write( "n=-2\r
\n" ); document.write( "\n" ); document.write( "10(-2)=(-2)+m
\n" ); document.write( "-20=-2+m
\n" ); document.write( "m=-18\r
\n" ); document.write( "\n" ); document.write( "10(-2)=(-2)+(-18)
\n" ); document.write( "(-18)=2+10(-2)
\n" ); document.write( "-20=-20
\n" ); document.write( "-18=-18
\n" ); document.write( "would this be the correct answer \n" ); document.write( "

Algebra.Com's Answer #129849 by checkley75(3666) $\"\"$ $\"About$

You can put this solution on YOUR website!
10x+y=10(x+y)
\n" ); document.write( "x=y+2
\n" ); document.write( "10(y+2)+y=10(y+2+y)
\n" ); document.write( "10y+20+y=10(2y+2)
\n" ); document.write( "11y+20=20y+20
\n" ); document.write( "11y-20y=0
\n" ); document.write( "y=0 ans. for the units integer.
\n" ); document.write( "x=0+2
\n" ); document.write( "x=2 for the tens integer
\n" ); document.write( "Proof:
\n" ); document.write( "10*2+0=10(2+0)
\n" ); document.write( "20+0=20
\n" ); document.write( "20=20\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );