document.write( "Question 174778: Can you please assist me in the following: A number is ten times the sum of its digits. The tens digit is two greater than the units digit. Find the number.\r
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document.write( "so far I only managed to write:\r
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document.write( "10n=n+m
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document.write( "m=2+10n\r
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document.write( "10n=n+(2+10n)
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document.write( "10n=n+2+10n
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document.write( "10n=11n+2
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document.write( "n=-2\r
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document.write( "10(-2)=(-2)+m
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document.write( "-20=-2+m
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document.write( "m=-18\r
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document.write( "10(-2)=(-2)+(-18)
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document.write( "(-18)=2+10(-2)
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document.write( "-20=-20
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document.write( "-18=-18
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document.write( "would this be the correct answer \n" );
document.write( "
Algebra.Com's Answer #129848 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Can you please assist me in the following: A number is ten times the sum of its digits. The tens digit is two greater than the units digit. Find the number. \n" ); document.write( "------------------------- \n" ); document.write( "Usually these problems involve a two-digit number. You have only two equation \n" ); document.write( "statements so I'm going to assume the number is 2-digit. \n" ); document.write( "------------------------ \n" ); document.write( "Let the number be 10t+u where t is the tens and u is the units digit. \n" ); document.write( "------------- \n" ); document.write( "Equations: \n" ); document.write( "10t+u = 10(t+u) \n" ); document.write( "t = u + 2 \n" ); document.write( "--------------- \n" ); document.write( "Rearrange: \n" ); document.write( "10t+u = 10t+10u \n" ); document.write( "9u = 0 \n" ); document.write( "u = 0 \n" ); document.write( "----------- \n" ); document.write( "Since t = u+2, t = 0+2 = 2 \n" ); document.write( "------------- \n" ); document.write( "The number is 20 \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |