document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174775>Question 174775</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 30 milSincePlease help me to solve the problem below. I have tried to solve it using the average speed formula S=D/T, but it did not work. The result I got make no sense (30=0).<BR>\n" );
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document.write( "A car went around a one mile track at a speed of 30 miles per hour. At what speed must the car travel on its second time around the track if the driver wants to average 60 miles per hour for the two mile trip?\r<BR>\n" );
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document.write( "Thank you very much in advance for your help.<BR>\n" );
document.write( "Camelia </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129847 by </B><A HREF=/tutors/aboutme.mpl?userid=actuary><B>actuary(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=actuary><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129847\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the car traveled the first lap (one mile) at 30 miles per hour, it took 2 minutes (T= D/S = 1 mile/30 mph = 1/30 hour = 2 minutes)to finish the first lap. Since the goal is is to cover the track twice (2 miles) at an average speed of 60 miles per hour, the car will take T = D/S<BR>\n" );
document.write( "2 miles/60 mph = 1/30 hour = 2 minutes for both laps. \r<BR>\n" );
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document.write( "I'm getting the same nonsensical answer as you did.  Are you sure that you transcribed the problem correctly? </SPAN>\n" );
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