document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174772>Question 174772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line that has a y intercept of -2 and is perpendicular to the graph of 3x + 6y=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129835 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find an equation of the line that has a y intercept of -2 and is perpendicular to the graph of 3x + 6y=2<BR>\n" );
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document.write( "Ok.  First, find the slope (m) of 3x+6y = 2 by putting it into slope-intercept form (y = mx + b).<BR>\n" );
document.write( "3x+6y = 2<BR>\n" );
document.write( "6y = -3x + 2<BR>\n" );
document.write( "y = (-1/2)x + 1/3<BR>\n" );
document.write( "The slope is -1/2.  Lines perpendicular will have the negative inverse slope, or +2.<BR>\n" );
document.write( "Now we know the slope (2) and the y-intercept is -2, so that's the point (0,-2).<BR>\n" );
document.write( "y-y1 = m*(x-x1) where (x1,y1) is the point (0,-2)<BR>\n" );
document.write( "y+2 = 2*(x-0)<BR>\n" );
document.write( "y+2 = 2x<BR>\n" );
document.write( "Or, 2x-y = 2<BR>\n" );
document.write( "In slope intercept form, it's y = 2x - 2, so the y-intercept is 2, as spec'd.<BR>\n" );
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