document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174742>Question 174742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a diagonal of a square lies on the line 3x-5y=14. one vertex is at (0,4). Find an equation of the line that contains the other diagonal. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129809 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129809\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a diagonal of a square lies on the line 3x-5y=14. one vertex is at (0,4). Find an equation of the line that contains the other diagonal.<BR>\n" );
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document.write( "The diagonals of a square are perpendicular, so the 2nd one will have a slope that's the negative inverse of 3x-5y=14.<BR>\n" );
document.write( "The slope, m1, of 3x-5y=14 is 3/5, so m2 will be -5/3.<BR>\n" );
document.write( "There are an infinite number to choose from, notice it says \"an equation.\"<BR>\n" );
document.write( "If we have the 2nd diagonal pass thru the point (4,0), then find the equation:<BR>\n" );
document.write( "y-y1 = m2*(x-x1) where (x1,y1) is the point (4,0)<BR>\n" );
document.write( "y = (-5/3)*(x-4)<BR>\n" );
document.write( "y = (-5/3)x + 20/3<BR>\n" );
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