document.write( "Question 174712This question is from textbook California Algebra 2
\n" ); document.write( ": 62. Mrs. Chavez invested $6000. She invested the money in two accounts-one with a 4% simple interest and the other with a 6% simple interest. At the end of the year, the total amount she earned in interest was $320. How much did Mrs. Chavez invest in each account? \n" ); document.write( "

Algebra.Com's Answer #129760 by Mathtut(3670) $\"\"$ $\"About$

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lets call the amount invested at 4% and 6%, a and b respectively
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\n" ); document.write( "a+b=6000.........eq 1
\n" ); document.write( ".04a+.06b=320....eq 2
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\n" ); document.write( "rewrite eq 1 to a=6000-b and place that value into eq 2
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\n" ); document.write( ".04(6000-b)+.06b=320
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\n" ); document.write( "240-.04b+.06b=320
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\n" ); document.write( ".02b=80
\n" ); document.write( ":
\n" ); document.write( " $\"highlight%28b=4000%29\"$ dollars invested at 6%
\n" ); document.write( ":
\n" ); document.write( " $\"a=6000-b=6000-4000=highlight%282000%29\"$ dollars invested at 4% \n" ); document.write( "

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