document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174707>Question 174707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.Write the equation of a line with a slope of 2 if f(-1)=5.\r<BR>\n" );
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document.write( "2. For each equation describe the SHAPE of the graph:\r<BR>\n" );
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document.write( "a) x-2y=4<BR>\n" );
document.write( "b) y=(x)(x)-4<BR>\n" );
document.write( "c)y=the absolute value of x+4<BR>\n" );
document.write( "d) y-2= -(x+2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129757 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.Write the equation of a line with a slope of 2 if f(-1)=5. <BR>\n" );
document.write( "f(-1) = 5 means that when x = -1, y = 5, so that's the point (-1,5).<BR>\n" );
document.write( "Now the problem is to find the eqn of the line thru (-1,5) with a slope of m=2.<BR>\n" );
document.write( "y - y1 = m*(x - x1) where (x1,y1) is the point (-1,5)<BR>\n" );
document.write( "y-5 = 2*(x - (-1))<BR>\n" );
document.write( "y-5 = 2x + 2<BR>\n" );
document.write( "y = 2x + 7<BR>\n" );
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document.write( "2. For each equation describe the SHAPE of the graph: <BR>\n" );
document.write( "a) x-2y=4<BR>\n" );
document.write( "It's a linear eqn, so the graph is a straight line.  Put it into slope-intercept form: y = (1/2)x - 2 --> it has a slope of +1/2, and it crosses the y-axis at (0,-2).<BR>\n" );
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document.write( "b) y=(x)(x)-4<BR>\n" );
document.write( "Do you mean x^2 - 4? If so, it's a parabola symmetrical about the y-axis crossing the x-axis at (-2,0) and (2,0), and its vertex is at (0,-4).<BR>\n" );
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document.write( "c)y=the absolute value of x+4<BR>\n" );
document.write( "d) y-2= -(x+2)<BR>\n" );
document.write( "y = -x<BR>\n" );
document.write( "A straight line thru the origin with a slope of -1.<BR>\n" );
document.write( " </SPAN>\n" );
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