document.write( "Question 174654: I can not locate given function and locate intercepts of the function can someone help me with these problems?\r
\n" ); document.write( "\n" ); document.write( "1. Given the function f(x)=-6x^2-12x-2, what is the domain of f?
\n" ); document.write( "A. real numbers b. {x\x>-1} the sign in the middle has a line under the lessthan. and a straigt line up and down at between the X's.
\n" ); document.write( "C. {x\x>or equal 1} or D. {x\xgreter or equal to-1} I choosen C. \r
\n" ); document.write( "\n" ); document.write( "2. Use a graph utility to graph the function over the indicated interval nad approx any local maxima nd local minima. If necessary, round answers to two decimals: f(x)=2+8x-x^2; (-5,5) here are the choices I have to pick:
\n" ); document.write( "a. local minimum at (4,50) B. local minimum at (4,18)
\n" ); document.write( "C. local minimum at (-4,18) D. local minimum at (-4,50)
\n" ); document.write( "I choosen A is that correct or where did I go wrong?\r
\n" ); document.write( "\n" ); document.write( "3. Find the average rate of change for the function between the given value:
\n" ); document.write( "f(x)= sqrt over 2x-1; from 1 to 5
\n" ); document.write( "A. 1/2 B. -28 C. -1/6 D. -2 I choosen B. is that correct?\r
\n" ); document.write( "\n" ); document.write( "4. Locate any intercept of the function.
\n" ); document.write( "f(x) = { on the side of -3x+9 and underneath 9x-3 if x<1 and underneath if v>1 with a line under the >
\n" ); document.write( "The answer if have to choose from is:
\n" ); document.write( "A. (0,3) B. (0,3),(3,0),(1/3,0) C. (0,9),(3,0),(1/3,0) D. (0,9)
\n" ); document.write( "I have choosen D is that correct..
\n" ); document.write( "I need some help and cannot find these in the book...
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Algebra.Com's Answer #129697 by nycsub_teacher(90)\"\" \"About 
You can put this solution on YOUR website!
Please list your questions one at a time instead of all questions in one post.\r
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\n" ); document.write( "\n" ); document.write( "3. Find the average rate of change for the function between the given value:
\n" ); document.write( "f(x)= sqrt over 2x-1; from 1 to 5\r
\n" ); document.write( "\n" ); document.write( "A. 1/2 B. -28 C. -1/6 D. -2 I choosen B. is that correct? \r
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\n" ); document.write( "\n" ); document.write( "Hello. I will go over the question again SLOWLY. Perhaps I made a mistake. If so, I'll let you know along the way. You said we need to \"square over.\" I assume (2x - 1) lies in the radicand, right? \r
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\n" ); document.write( "\n" ); document.write( "I will assume that you are talking about the square root of the quantity (2x - 1), which is written as sqrt{2x - 1}.\r
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\n" ); document.write( "\n" ); document.write( "The average rate of change formula = [f(b) - f(a)]/(b - a)\r
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\n" ); document.write( "\n" ); document.write( "You were given a function over the interval [1, 5], which means from 1 to 5.\r
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\n" ); document.write( "\n" ); document.write( "In this case, a = 1 and b = 5.\r
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\n" ); document.write( "\n" ); document.write( "We now search for f(b), then we search for f(a).\r
\n" ); document.write( "\n" ); document.write( "Once we have those two guys, we plug them into the formula above and simplify.\r
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\n" ); document.write( "\n" ); document.write( "Are you with me so far?\r
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\n" ); document.write( "\n" ); document.write( "Remember, b = 5 and a = 1 from the given interval.\r
\n" ); document.write( "\n" ); document.write( "We plug each number into the function and simplify. By doing so, we will find f(b) and f(a).\r
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\n" ); document.write( "\n" ); document.write( "Here it is:\r
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\n" ); document.write( "\n" ); document.write( "f(x) = sqrt{2x - 1}\r
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\n" ); document.write( "\n" ); document.write( "f(5) = sqrt{2(5) - 1}\r
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\n" ); document.write( "\n" ); document.write( "f(5) = sqrt{10 - 1}\r
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\n" ); document.write( "\n" ); document.write( "f(5) = sqrt{9}\r
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\n" ); document.write( "\n" ); document.write( "f(5) = 3\r
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\n" ); document.write( "\n" ); document.write( "This means that f(5) = 3 = f(b)\r
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\n" ); document.write( "\n" ); document.write( "I see what happened. I made a mistake.\r
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\n" ); document.write( "\n" ); document.write( "The square root of 9 is 3 not 9.\r
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\n" ); document.write( "\n" ); document.write( "So, f(b) = 3 NOT 9.\r
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\n" ); document.write( "\n" ); document.write( "Sorry about that....\r
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\n" ); document.write( "\n" ); document.write( "We now find f(a).\r
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\n" ); document.write( "\n" ); document.write( "f(1) = sqrt{2(1) - 1}\r
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\n" ); document.write( "\n" ); document.write( "f(1) = sqrt{2 - 1}\r
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\n" ); document.write( "\n" ); document.write( "f(1) = sqrt{1}\r
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\n" ); document.write( "\n" ); document.write( "f(1) = 1 = f(a).\r
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\n" ); document.write( "\n" ); document.write( "We can now plug that info into the formula and simplify.\r
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\n" ); document.write( "\n" ); document.write( "average rate of change = (3 - 1)/(5 - 1)\r
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\n" ); document.write( "\n" ); document.write( "average rate of change = 2/4 = 1/2\r
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\n" ); document.write( "\n" ); document.write( "Dawn, I apologize. The correct answer is 1/2.\r
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