document.write( "Question 174658: A mixture is 90% water. The water weighs 20lbs. The mixture rests for 24 hours and is now only 50% water. No evaporation has occurred. Now how much does the water weigh? \n" ); document.write( "

Algebra.Com's Answer #129688 by Mathtut(3670) $\"\"$ $\"About$

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I am changing my answer: since 90% of the mixture is 100% water then 50% of the mixture is 55.56% water...therefore we lost 44.44% of the weight or retained 55.56% of its weight
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\n" ); document.write( ".5556(20)=11.112 pounds....\r
\n" ); document.write( "\n" ); document.write( " that being said the water had to evaporate......I believe the assumption is that the other part of the mixture doesnt evaporate.
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\n" ); document.write( "Very strange problem as the mixture could be 90% by weight or volume....alot of questions on this problem.....imo it isnt written very well.\r
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\n" ); document.write( "If someone has a better explanation I hope they post it...... \n" ); document.write( "

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