document.write( "Question 174652: If sq root(3-x) = 1 - sq root(2x), then 9x^2 =
\n" ); document.write( "(A) 5
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\n" ); document.write( "(C) 2 - 3x
\n" ); document.write( "(D) 12 - 4x
\n" ); document.write( "(E) 20x - 4\r
\n" ); document.write( "\n" ); document.write( "thanks for your help
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Algebra.Com's Answer #129687 by SAT Math Tutor(36)\"\" \"About 
You can put this solution on YOUR website!
First, square both sides of the equation to get:\r
\n" ); document.write( "\n" ); document.write( "1. 3 - x = 1 - 2\"sqrt%282x%29\" + 2x\r
\n" ); document.write( "\n" ); document.write( "2. 3 - x = 1 - \"sqrt%288x%29\" + 2x\r
\n" ); document.write( "\n" ); document.write( "Then, move 2x to the left hand side and 3 to the right hand side:\r
\n" ); document.write( "\n" ); document.write( "3. -3x = -2 - \"sqrt%288x%29\"\r
\n" ); document.write( "\n" ); document.write( "Next, we will square both sides again, but first note that:\r
\n" ); document.write( "\n" ); document.write( "4. 3x - 2 = \"sqrt%288x%29\"\r
\n" ); document.write( "\n" ); document.write( "We will use that in a second, now square both sides from step 3:\r
\n" ); document.write( "\n" ); document.write( "5. 9x^2 = 4 + 4\"sqrt%288x%29\" + 8x\r
\n" ); document.write( "\n" ); document.write( "Now, plug in what we have for step 4 into step 5:\r
\n" ); document.write( "\n" ); document.write( "6. 9x^2 = 4 + 4(3x - 2) + 8x\r
\n" ); document.write( "\n" ); document.write( "Simplify:\r
\n" ); document.write( "\n" ); document.write( "9x^2 = 4 + 12x - 8 + 8x\r
\n" ); document.write( "\n" ); document.write( "9x^2 = 20x - 4
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