document.write( "Question 174628This question is from textbook Amsco's Preparing for the Regents Examination Mathematics B
\n" ); document.write( ": 6) If 4^x = 2^y and 9^x-1 = 3^x+1, which of the following are the values of x and y?
\n" ); document.write( " (a) x = 2, y = 4 (b) x=3, y=6 (c) x=4, y=2 (d) x=6, y=3\r
\n" ); document.write( "\n" ); document.write( "7)When David was born, his grandparents deposited $1,000 in a college account that promised 4 percent interest compounded annually for 18 years. Which of the following equations shows the worth of the account when David is 18?
\n" ); document.write( " (a) y = 18(4)($1,000)
\n" ); document.write( " (b) y = 18(0.04)($1,000)
\n" ); document.write( " (c) y = $1,000(0.04)^18
\n" ); document.write( " (d) y = $1,000(1.04)^18\r
\n" ); document.write( "\n" ); document.write( "Show work thanks so much!
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Algebra.Com's Answer #129663 by ankor@dixie-net.com(22740)\"\" \"About 
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6) If 4^x = 2^y and 9^x-1 = 3^x+1, which of the following are the values of x and y?
\n" ); document.write( ":
\n" ); document.write( "In the 1st equation, we can write 4^x as 2^(2x), so we have
\n" ); document.write( "2^(2x) = 2^y
\n" ); document.write( "Therefore:
\n" ); document.write( "2x = y
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\n" ); document.write( "In the 2nd equation, the same:
\n" ); document.write( "3^(2(x-1)) = 3^(x+1)
\n" ); document.write( "therefore
\n" ); document.write( "2(x-1) = x + 1
\n" ); document.write( "2x - 2 = x + 1
\n" ); document.write( "2x - x = 1 + 2
\n" ); document.write( "x = 3
\n" ); document.write( "2x = y, therefore
\n" ); document.write( "y = 6
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "7)When David was born, his grandparents deposited $1,000 in a college account that promised 4 percent interest compounded annually for 18 years. Which of the following equations shows the worth of the account when David is 18?
\n" ); document.write( ":
\n" ); document.write( "The interest is added to the accumulated amt each year for 18 yrs, therefore:
\n" ); document.write( "(d) 1000*(1.04)^18
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