document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174630>Question 174630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help sketching these<BR>\n" );
document.write( "A rectangle is three times as long as it is wide. If its length and width are both decreased by 2cm, its area is decreased by 36cm^2. Find its original dimensions. Make a sketch </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129657 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3w<BR>\n" );
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document.write( "Let L be the length, w be the width and A be the original area.<BR>\n" );
document.write( "L*w=A<BR>\n" );
document.write( "(L-2)(w-2)=A-36<BR>\n" );
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document.write( "Substitute 3w for L in both equations.<BR>\n" );
document.write( "3w*w=A<BR>\n" );
document.write( "(3w-2)(w-2)=A-36<BR>\n" );
document.write( ".<BR>\n" );
document.write( "3w^2=A<BR>\n" );
document.write( "3w^2-8w+4=A-36<BR>\n" );
document.write( ".<BR>\n" );
document.write( "3w^2-8w+4=3w^2-36 substitute 3w^2 for A<BR>\n" );
document.write( "-8w+4=-36<BR>\n" );
document.write( "-8w=-40<BR>\n" );
document.write( "w=5<BR>\n" );
document.write( "L=15<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );