document.write( "Question 24316: 9x+6y=14
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document.write( "3x+2y=11
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document.write( "Solve for x and y\r
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document.write( "I know that you have to use substitution but i keep getting answers like,
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document.write( "9x+66-9x=14 so it is going to turn out with your x's turning into a zero and you come out with 0=52 and that is obviousley not true...PLEASE HELP ASAP I have been working on this for at least an hour\r
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document.write( "i looked for examples similiar to this problem but i could'nt find any
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Algebra.Com's Answer #12964 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE MY COMMENTS BELOW. \n" ); document.write( "9x+6y=14 \n" ); document.write( "3x+2y=11 \n" ); document.write( "Solve for x and y \n" ); document.write( "I know that you have to use substitution but i keep getting answers like, \n" ); document.write( "9x+66-9x=14 so it is going to turn out with your x's turning into a zero and you come out with 0=52 and that is obviousley not true. \n" ); document.write( "THERE IS NOTHING WRONG WITH YOU !POOR BOY !YOU HAVE BEEN TRYING TOO HARD TO ACHIEVE THE IMPOSSIBLE.SEE A PROBLEM GIVEN BELOW TO UNDERSTAND THE PHENOMENA. \n" ); document.write( "SO BELIEVE IN YOUR SELF ,YOUR WORK AND SAY FIRMLY THERE IS NO SET OF VALUES OF X AND Y WHICH SATISFY THE 2 GIVEN EQUATIONS.SEE MY COMMENTS AT THE END OF THE EXAMPLE BELOW FOR A SPECIFIC POINT ON YOUR PROBLEM.. \n" ); document.write( "..PLEASE HELP ASAP I have been working on this for at least an hour \n" ); document.write( "i looked for examples similiar to this problem but i could'nt find any \n" ); document.write( "***************************************************************** \n" ); document.write( "In the given system of equations is consistent and dependent, consistent and independent or inconsistent. \n" ); document.write( "3x-y=7 \n" ); document.write( "6x-2x=9 \n" ); document.write( "what does these terms mean? \n" ); document.write( "1 solutions\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------- \n" ); document.write( "Answer 12951 by venugopalramana(684) on 2006-01-13 01:20:47 (Show Source): \r \n" ); document.write( "\n" ); document.write( "IS the given system of equations consistent \n" ); document.write( "MEANS WHETHER THERE IS ANY SET OF VALUES FOR X AND Y WHICH SATISFIES BOTH THE GIVEN EQUATIONS. \n" ); document.write( "and dependent,MEANS WHETHER ONE EQUATION CAN BE GOT FROM THE OTHER BY SUITABLE AND PERMISSIBLE TRANSFORMATION \n" ); document.write( "consistent and independent,MEANS THAT ONE EQUATION CANNOT BE OBTAINED FROM THE OTHER EQUATION BY BY ANY SUITABLE AND PERMISSIBLE TRANSFORMATION . \n" ); document.write( "or inconsistent.MEANS THERE ARE NO SET OF VALUES FOR X AND Y WHICH SATISFY BOTH THE EQUATIONS. \n" ); document.write( "3x-y=7.....I....... \n" ); document.write( "6x-2x=9...I THINK IT SHOULD BE 6X-2Y=9........II \n" ); document.write( "what does these terms mean?NOW I THINK YOU KNOW WHAT THE TERMS MEAN.THERE ARE TESTS FOR FINDING THESE SITUATIONS.WE SHALL RESTRICT THE ANALYSIS TO YOUR PROBLEM AFTER THE CORRECTION MENTIONED ABOVE. \n" ); document.write( "WE FIND THAT ON L.H.S OF THE 2 EQNS.WE HAVE 3X-Y AND 6X-2Y WHICH ARE DIRECT MULTIPLES BY 2 .THAT IS WE GET LHS OF EQN.2 BY MULTIPLYING THE EQN 1 WITH 2 \n" ); document.write( "WE GET EQN.I *2 ....6X-2Y=14 \n" ); document.write( "WHERE AS EQN.II SAYS 6X-2Y=9..SO IF WE TRY TO SATISFY EQN.I ,EQN II WILL NOT BE SATISFIED AND IF WE TRY TO SATISFY EQN II ,EQN.I WILL NOT BE SATISFIED.SO THERE ARE NO VALUES OF X AND Y WHICH SATISFY BOTH EQUATIONS.SO WE SAY THE GIVEN EQNS. ARE INCONSISTENT. \n" ); document.write( "**************************************************************************** \n" ); document.write( "IN YOUR PROBLEM THE LHS OF FIRST EQN IS OBTAINED BY MULTIPLYING WITH 3 THE LHS OF SECOND EQN \n" ); document.write( "SO 9X+6Y=42 AND NOT 11 AS GIVEN HENCE THEY ARE INCONSISTENT AND THERE IS NO SOLUTION.IF YOU WANT TO LEARN MORE ON THIS COME BACK .\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |