document.write( "Question 174571: x^2 + y^2 <= 1
\n" ); document.write( "(x-1)^2 + y^2 <= 1
\n" ); document.write( "Is it possible to find x and y? \n" ); document.write( "

Algebra.Com's Answer #129586 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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x^2 + y^2 <= 1
\n" ); document.write( "(x-1)^2 + y^2 <= 1
\n" ); document.write( "---------------------subtraction eliminates y^2
\n" ); document.write( "x^2 - (x-1)^2 <= 0
\n" ); document.write( "Foil
\n" ); document.write( "x^2 - (x^2 - 2x + 1) =< 0
\n" ); document.write( "Remove brackets
\n" ); document.write( "x^2 - x^2 + 2x - 1 =< 0
\n" ); document.write( "2x - 1 =< 0
\n" ); document.write( "2x =< + 1
\n" ); document.write( "x =< .5
\n" ); document.write( ":
\n" ); document.write( "Find y using x^2 + y^2 =< 1
\n" ); document.write( ".5^2 + y^2 =< 1
\n" ); document.write( ".25 + y^2 =< 1
\n" ); document.write( "y^2 =< 1 -.25
\n" ); document.write( "y^2 =< .75
\n" ); document.write( "y =< +/- $\"sqrt%28.75%29\"$
\n" ); document.write( "y =< .866
\n" ); document.write( "y => -.866 \n" ); document.write( "

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