document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=174544>Question 174544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> p+(-8)<(and equal to) -12\r<BR>\n" );
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document.write( "This problem is from the glencoe pre-algebra practice workbook.  Isbn:  0-07-827789-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #129555 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=129555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just add +8 to each side of the inequality:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%2B%28-8%29+%2B8+%3C=-12+%2B8 ALIGN=MIDDLE  ALT=\"p%2B%28-8%29+%2B8+%3C=-12+%2B8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%3C=-4 ALIGN=MIDDLE  ALT=\"p%3C=-4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "R^2 </SPAN>\n" );
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