document.write( "Question 174543: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working togeter to mix 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #129554 by rapaljer(4671) You can put this solution on YOUR website! If Steven can mix 20 drinks in 5 minutes, then in 1 minute he can mix 4 drinks. \n" ); document.write( "If Sue can mix 20 drinks in 10 minutes, then in 1 minute she can mix 2 drinks. \n" ); document.write( "If Jack can mix 20 drinks in 15 minutes, then in 1 minute he can mix 20/15 =4/3 drinks.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x = time it will take all 3 mixing drinks together to mix 20 drinks. \r \n" ); document.write( "\n" ); document.write( "Then in 1 minute, all will be able to mix 20/x drinks.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, number of drinks of Steven in 1 minute + no drinks by Sue in 1 minute + no drinks by Jack in 1 minute = Number of drinks by all in 1 minute.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by the LCD which is 3x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 \n" ); document.write( " |