document.write( "Question 174543: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working togeter to mix 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #129554 by rapaljer(4671)\"\" \"About 
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If Steven can mix 20 drinks in 5 minutes, then in 1 minute he can mix 4 drinks.
\n" ); document.write( "If Sue can mix 20 drinks in 10 minutes, then in 1 minute she can mix 2 drinks.
\n" ); document.write( "If Jack can mix 20 drinks in 15 minutes, then in 1 minute he can mix 20/15 =4/3 drinks.\r
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\n" ); document.write( "\n" ); document.write( "Let x = time it will take all 3 mixing drinks together to mix 20 drinks. \r
\n" ); document.write( "\n" ); document.write( "Then in 1 minute, all will be able to mix 20/x drinks.\r
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\n" ); document.write( "\n" ); document.write( "Now, number of drinks of Steven in 1 minute + no drinks by Sue in 1 minute + no drinks by Jack in 1 minute = Number of drinks by all in 1 minute.\r
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\n" ); document.write( "\n" ); document.write( "\"4+%2B+2+%2B+4%2F3+=+20%2Fx\"
\n" ); document.write( "\"6+%2B+4%2F3+=+20%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by the LCD which is 3x:
\n" ); document.write( "\"3x%2A6+%2B+3x%2A%284%2F3%29+=+3x%2A%2820%2Fx%29+\"
\n" ); document.write( "\"18x+%2B+4x+=+60\"
\n" ); document.write( "\"22x+=+60\"
\n" ); document.write( "\"x=+60%2F22+=+30%2F11=+2.7\" minutes (approximately)\r
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\n" ); document.write( "\n" ); document.write( "R^2
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