document.write( "Question 24381: I was doing my homework and came across a problem. Can you help me. Logarithmic properties.
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document.write( "logsub3 12to the power of 5/6 Xto the power of 9 \n" );
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Algebra.Com's Answer #12953 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! logsub3 12to the power of 5/6 Xto the power of 9\r\n" ); document.write( "\r\n" ); document.write( "log3(125/6)9\r\n" ); document.write( "\r\n" ); document.write( "use rule of exponents (BA)C = BAC\r\n" ); document.write( "\r\n" ); document.write( "log3125/6·9\r\n" ); document.write( "\r\n" ); document.write( "log31215/2\r\n" ); document.write( "\r\n" ); document.write( "now use the rule of logs: logBAC = C·logBA\r\n" ); document.write( "\r\n" ); document.write( "15/2·log312\r\n" ); document.write( "\r\n" ); document.write( "Now write 12 in terms of the base 3, i.e., 12 = (3·4)\r\n" ); document.write( "\r\n" ); document.write( "15/2·log3(3·4)\r\n" ); document.write( "\r\n" ); document.write( "Nou use the rule of logs: logB(AC) = (logBA + logBC)\r\n" ); document.write( "\r\n" ); document.write( "15/2(log33 + log34)\r\n" ); document.write( "\r\n" ); document.write( "Finally use the rule of logs logBB = 1\r\n" ); document.write( "\r\n" ); document.write( "15/2(1 + log34)\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r\n" ); document.write( "AnlytcPhil@aol.com\n" ); document.write( " |