document.write( "Question 173155: sorry, these problems aren't from a textbook. I've started these four problems then just started going in circles to find the answer.
\n" ); document.write( "1.)Solve for x, where x is between 0 and 2pie
\n" ); document.write( "tan^(2)x-tanx-3=0\r
\n" ); document.write( "\n" ); document.write( "2.)verify the identity:
\n" ); document.write( "sinx/1-cos=cscx+cotx
\n" ); document.write( "where 0\n" ); document.write( "\n" ); document.write( "3.)evaluate:
\n" ); document.write( "cos[sin^(-1)(3/5)]\r
\n" ); document.write( "\n" ); document.write( "4.) Given that sin theta =1/2, theta in Q1 and cos beta =1/2, find cos (theta-bata)\r
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Algebra.Com's Answer #129520 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!
1.)Solve for x, where x is between $\"0\"$ and $\"2pi\"$
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document.write( "Write  for \r\n" );
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document.write( "That doesn't factor, so we use the quadratic formula:\r\n" );
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document.write( "with , , and :\r\n" );
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document.write( "Using the +\r\n" );
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document.write( "Replace  by \r\n" );
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document.write( "Use inverse tangent key on calculator,\r\n" );
document.write( "with calculator in radian mode:\r\n" );
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document.write( "However, the calculator only gives the\r\n" );
document.write( "answer which is in quadrant I.  There is\r\n" );
document.write( "also another answer in quadrant III, because\r\n" );
document.write( "the tangent is also positive in quadrant III.\r\n" );
document.write( "To get that, we add :\r\n" );
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document.write( "Using the minus:\r\n" );
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document.write( "Use inverse tangent key on calculator,\r\n" );
document.write( "with calculator in radian mode:\r\n" );
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document.write( "However, the calculator only gives the\r\n" );
document.write( "negative answer which is in quadrant IV,\r\n" );
document.write( "taken as a negative angle. However to get\r\n" );
document.write( "a coterminal angle between 0 and ,\r\n" );
document.write( "we add :\r\n" );
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document.write( "There is also another answer in quadrant II,\r\n" );
document.write( "because the tangent is also negative in quadrant IV.\r\n" );
document.write( "To get that, we add  to the\r\n" );
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document.write( "2.)verify the identity:\r\n" );
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document.write( "3.)evaluate:\r\n" );
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document.write( "Let's draw the picture of \r\n" );
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document.write( "That means the angle whose sine is \r\n" );
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document.write( "The inverse sine by definition is always between \r\n" );
document.write( " and . Thus the angle  is in Quadrant I because \r\n" );
document.write( "is a positive number.\r\n" );
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document.write( "Since the sine =  we will let y be\r\n" );
document.write( "the numerator of  and r be the\r\n" );
document.write( "denominator.  \r\n" );
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document.write( "The angle  is\r\n" );
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document.write( "Now we need the cosine of this angle, which is , so\r\n" );
document.write( "we will need the value of .  We use the Pythagorean theorem,\r\n" );
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document.write( "So now we have , so we put that in:\r\n" );
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document.write( "Therefore the cosine of that angle is  or \r\n" );
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document.write( "So,\r\n" );
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document.write( "If I have time I'll come back to this:\r\n" );
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document.write( "4.) Given that sin theta =1/2, theta in Q1 and cos beta =1/2, find cos (theta-bata)\r\n" );
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document.write( "Edwin

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