document.write( "Question 24382: In an experiment two six-sided dice are tossed, what is the probablility of not getting a sum of ten? \n" ); document.write( "

Algebra.Com's Answer #12950 by askmemath(368) $\"\"$ $\"About$

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An easier way to approach this problem would be to work backwards.
\n" ); document.write( "What is the probability of getting a ten?
\n" ); document.write( "First of all, in how many ways can you get a score of 10?
\n" ); document.write( "6,4
\n" ); document.write( "4,6
\n" ); document.write( "5,5 which means 3 ways.
\n" ); document.write( "Since we are throwing two 6 faced die,total number of ways of getting a value = 6x6 = 36
\n" ); document.write( "Which means the probability of throwing a 10 is $\"3%2F36\"$ = $\"+1%2F12\"$ \r
\n" ); document.write( "\n" ); document.write( "Now, the number of ways of not getting a 10 will be Total Probability - Total Probability of throwing a 10
\n" ); document.write( "= $\"1+-+1%2F12\"$ = $\"11%2F12\"$ \n" ); document.write( "

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